Cluster · Simplification with Exponents and Roots

d
Clusters / #1326
tight score 0.00

Simplification with Powers and Roots
Questions
276
Questions in this cluster
275 total
Question Category Subtype Difficulty

What value will come in the place of question mark (?) in the following questions?

(47)2 + 6 × (26)2 – 805 × 6 = ?

pipeline-1170699
up_police intermediate

362 – √2704 – 3675 ÷ 72 × 8.4 = ?

pipeline-500651
rpf intermediate

What value will come in place of question mark (?) in the following question?

(8)3 – 128.1 ÷ 2.1 + 0.625 × 96 × 32.5 = (?)4

pipeline-500667
rpf intermediate

What value will come in place of question mark (?) in the following question?

[(1152 ÷ 80 × 2.5)1/2 + (414 ÷ 23)2] = (?)3 + 114

pipeline-484295
rpf intermediate

Find the value of '?':

(1369)1/2 - (2197)1/3+ 276 - ?2 = (4225)1/2 + 171

pipeline-489676
rpf intermediate

(256)2 × 64 ÷ 165 × 4096 = 4? × 256

pipeline-1272390
banking intermediate

√16641 × √4096 – 85 × 95 + 73 = ?

pipeline-1285977
banking intermediate

(149)2 – (21)2 – √? = ? – 590

pipeline-1285979
banking intermediate

(35/81) × 38 × (9/27) = 3? × 243

pipeline-427641
banking intermediate

(1331)1/3 + √121 + 11 - 8% of 400 = ?

pipeline-1289254
banking intermediate

(0.25)4 × (0.125/0.5) × (0.5)8 = (0.5)? × 0.25

pipeline-1244148
banking intermediate

(256)2 × 64 ÷ 165 × 4096 = 4? × 256

pipeline-427636
banking intermediate

3√( 64/343) + 52 × 23/175 = ? × 32

pipeline-1289255
banking intermediate

(205.87 + 84.13) ÷ 25.85 + √144 = ?

pipeline-1272397
banking intermediate

√5041% of √3364 + 57 = ? + 678

pipeline-1272394
banking intermediate

(35/81) × 38 × (9/27) = 3? × 243

pipeline-1272395
banking intermediate

40% of 375 ÷ ∛512 × 30 = 4500 ÷ ?

pipeline-429686
banking intermediate

√[212 × 784 ÷ 686 + 432 ÷ 4.8 × 0.6 + 18] = ? - (804 ÷ 67)

pipeline-1270342
banking intermediate

25 × 1748 ÷ (2√1444) = ? + 15√289

pipeline-1270349
banking intermediate

√(√6084 + √1764 + √576) = 0.6 × ?

pipeline-1285976
banking intermediate

23 + 22 × (27)1/3 + (216)1/3 = ?

pipeline-1289253
banking intermediate

√5625 + (6565/13) = ?2 + 22

pipeline-1285978
banking intermediate

√5041% of √3364 + 57 = ? + 678

pipeline-427640
banking intermediate

(0.0256) ÷ 0.064 × (0.4)8 = (0.4)? × 0.16

pipeline-1285969
banking intermediate

[35.7 ÷ (√289 × 15.3 ÷ 51)] + (?)2 = 536

pipeline-1270350
banking intermediate

? ={(6432)1/2 × (1300)1/2}/(8126)1/2

pipeline-1289256
banking intermediate

271.5 × [(3)3]= 275

pipeline-427637
banking intermediate

271.5 × [(3)3]= 275

pipeline-1272391
banking intermediate

√676 × √10201 + 49% of 700 – 54 = ?

pipeline-1285971
banking intermediate

√441 + (729 × 3-3) + 25% of 64 = ?

pipeline-1289252
banking intermediate

? = (1330.988)1/3 - (81.038)1/2

pipeline-1268399
banking intermediate

√? + 416 = (60% of 920) – 110

pipeline-1262970
banking intermediate

? = (343500)1/3 + (216600)1/3 + (125400)1/3 

pipeline-1268400
banking intermediate

[(3)3 × (5)4] ÷ (3)5 = ?

pipeline-1262967
banking intermediate

(18,792 ÷ 87)1/3 + (72 × 2)1/2 = (?)1/2

pipeline-1259935
banking intermediate

(?/ 529) = (324/?)

pipeline-1262966
banking intermediate

? = {(1295.56)1/4 + (2.084)5 - (5120.00978)1/9}1/2

pipeline-1268401
banking intermediate

\( \sqrt\frac{169}{25}\) + \(\frac{3^3×2^4}{5^2 }\)  \(-\frac{7×4^2}{3}\)

pipeline-1258485
banking intermediate

? = (27)0.68 + (16)1.55 + (243)0.21

pipeline-1269169
banking intermediate

(6√6 × 2√3 × 4√2) ÷ 12 = ? + 123 – 59

pipeline-1268412
banking intermediate

√? – {72 / (9×2) } × √784 = 895 – √1296 × 24

pipeline-1269173
banking intermediate

\(\frac{(9^2+5^2)×(7^2-4^2)}{(6×2^2)+(3^3-2^3)}\) = ?

pipeline-1259938
banking intermediate

(0.0625)× 0.125 ÷ (0.5)9 = (0.5)? ÷ 0.25

pipeline-1269174
banking intermediate

(16807)–2 × (49)7 × (1/343) = (7)?

pipeline-1269176
banking intermediate

337.8 × 331.2 ÷ 335 = 33 × 33?

pipeline-1259932
banking intermediate

(2 √288 –31) + (√8 – 6)2 = (?)2

pipeline-1268405
banking intermediate

63 × 34 ÷ 93 + ?2 = 72

pipeline-1269181
banking intermediate

(6√6 × 2√3 × 4√2) ÷ 12 = ? + 123 – 59

pipeline-1258416
banking intermediate

[(√2401 + √625) – (29 + 5)] ÷ 4 = ?1/2

pipeline-1258417
banking intermediate

52 + 132  – 112 = (?)3 – 52

 

pipeline-1256757
banking intermediate
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