Cluster · Simplification using BODMAS Rule
| Question | Category | Subtype | Difficulty | |
|---|---|---|---|---|
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Simplify the following expression: 133 ÷ 19 × 3 - 48 × 2 ÷ 24 + 841 ÷ [ {45 - 16 } ] pipeline-1155500
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delhi_police | — | intermediate | |
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Simplify: [\({1\over 5}\) of (35 - 5) + 4]2 - [9 - {7 + (2 - 3)} + 5]2 pipeline-1134989
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delhi_police | — | intermediate | |
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Simplify: 18 - [6 - {4 - (8.6 + 6.6 - 3.2)}] + 2 × 4 pipeline-1133738
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delhi_police | — | intermediate | |
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Find the value of 60 ÷ 5 × (\(\frac{9}{8}\)of \(\frac{4}{3}\)÷\(\frac{3}{4}\)of \(\frac{2}{3}\)). pipeline-1134982
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delhi_police | — | intermediate | |
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Find the value of [{(82 + 48 ÷ 8 × 3) + 5 × 6 } – 7.5 × 2] pipeline-1131337
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delhi_police | — | intermediate | |
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Simplify 65 ÷ 13 × 4 + (35 ÷ 7 × 9)2 + 100 ÷ 5 of 4 × 80 pipeline-1140079
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delhi_police | — | intermediate | |
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Evaluate 6.9 - [8.6 - {6.5 - (5.4 - \(\overline{4.3 - 2}\))}]. pipeline-1133740
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delhi_police | — | intermediate | |
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What is the value of \(\frac{14+7-12+15-17+2-3+17}{2+7-9+2-4+22}=?\) pipeline-1103327
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delhi_police | — | intermediate | |
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Find the value of: -67 + 700 ÷ [85 - {8 × 9 + (28 - 5 × 5)}] pipeline-1103318
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delhi_police | — | intermediate | |
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Simplify the following expression. 25 ÷ 5 + 3 of 2 − 4 + 6 of 3 ÷ 2 − 8 + 4 pipeline-1094763
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delhi_police | — | intermediate | |
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The value of 8 ÷ 2 of 3 - [56 ÷ 4 of {4 × 3 - (9 - 11) ÷ (2÷ 4 of 4)}] is: pipeline-1096963
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delhi_police | — | intermediate | |
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The value of \(4{1\over6} ÷25×75÷{1\over5} of125\) is: pipeline-1094758
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delhi_police | — | intermediate | |
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The value of [0.004 × {5 ÷ (21 - 6) × 3} + 0.8] lies between: pipeline-1106893
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delhi_police | — | intermediate | |
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Simplify: 8.2 + 2.6 + 3.2 - 4.5 ÷ 0.9 × 1.2 pipeline-1106894
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delhi_police | — | intermediate | |
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Find the value of the given expression: 10 ÷ 5 × 1 + 3 - [8 - {5 - (7 - 7 - 9)}] pipeline-1083751
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delhi_police | — | intermediate | |
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The value of 3\(\frac{1}{3}\) ÷ 2 \(\frac{1}{2}\) of 1\(\frac{3}{5}\) + ( \(\frac{3}{8}\) + \(\frac{1}{7}\) × 1\(\frac{3}{4}\)) is: pipeline-1085505
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delhi_police | — | intermediate | |
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What is the value of 12 - [3 + {4 of 2 ÷ 8 - (8 - 6 ÷ 3)}] pipeline-1085509
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delhi_police | — | intermediate | |
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Simplify. 963 + 306 × 102 ÷ 6 - 86 + (218 - 15) pipeline-1257080
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delhi_police | — | intermediate | |
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Simplify: \(\frac{1-\frac{3}{7}\div\frac{9}{49}\times \frac{3}{14}}{1+\frac{3}{5}\div\frac{1}{25}\times \frac{1}{30}}\) pipeline-1251263
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delhi_police | — | intermediate | |
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Simplify: 25 - ( 18 - 4 × 9 ÷ 3) pipeline-1203336
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delhi_police | — | intermediate | |
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Simplify \(- {7\over6}+{4\over9}\div{5\over3}\times{1\over16}\) pipeline-1224572
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delhi_police | — | intermediate | |
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Simplify: 20 × [24 ÷ 105 × {75 × 119 ÷ (15 × 17) }] pipeline-1194953
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delhi_police | — | intermediate | |
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\(9\div \bigg [1 + \left\{ 4 \times \bigg( {5\over6} - {\overline{{1\over3} + {1\over2}} } \bigg) \right\} \bigg]\) is equal to: pipeline-1201030
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delhi_police | — | intermediate | |
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Simplify: 8 ÷ [(9 - 5) ÷ {(7 - 2) ÷ (3 + 9 ÷ 24)}] pipeline-1161189
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delhi_police | — | intermediate | |
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The value of \(1\frac{2}{5}-[3\frac{3}{4}\div({1\frac{1}{4}\div\frac{1}{2}(1\frac{1}{2}\times 3\frac{1}{3}\div1\frac{1}{3}))}]\) is: pipeline-1139984
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delhi_police | — | intermediate | |
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Find the value of \((\frac{1}{4}\times \frac{3}{4} \div 1\frac{1}{4} of \frac{2}{5})\div(\frac{3}{4}\div1\frac{2}{3}of\frac{4}{5})-(\frac{1}{2}-\frac{1}{2}\times\frac{1}{4})\). pipeline-1133336
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delhi_police | — | intermediate | |
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Simplify: \([( {1\over6} \div {1\over9} \times {2\over3}) \times 18 + 5]\) pipeline-1102529
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delhi_police | — | intermediate | |
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What is the value of (119 + 114 - 17) ÷ {6 × (12 + 3 of 2)}? pipeline-1106481
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delhi_police | — | intermediate | |
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Simplify 6 + [(16 - 4) \(\div \)(22 + 2)] - 2 pipeline-1133043
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delhi_police | — | intermediate | |
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Simplify : 155 - [224 ÷ (8 × 4) - (-4) - {3 - 17 - 10}] pipeline-1101729
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delhi_police | — | intermediate | |
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The value of 40 \(\div\)5 of 2 \(\times[18 \div 6 \times (12 - 9) \) of 5 - (3-8)] \(\div\) 25 is: pipeline-1094565
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delhi_police | — | intermediate | |
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Solve: (4 + 2) of 9 − 6 × 2 + \(\frac{5}{5} \) pipeline-1096508
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delhi_police | — | intermediate | |
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The value of [15 ÷ 3 × 7 − 8 of 2 + 6] is: pipeline-1094310
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delhi_police | — | intermediate | |
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The value of 96 of 10 - 40 + 19 \(\div\) [{70 + (40 - 22) \( \div\) 3} \( \div\) 4] is : pipeline-1089934
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delhi_police | — | intermediate | |
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What is the value of (84 ÷ 12 × 3 − 4 ÷ 12 × 9 + 5 × 6 − 2 × 3)/(8 ÷ 12 × 3) pipeline-1084047
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delhi_police | — | intermediate | |
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Simplify, \(0.25 \ of \ 63 + (2\dfrac{4}{5}-3\dfrac{9}{10}) \div 1.10 \) pipeline-1082765
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delhi_police | — | intermediate | |
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Simplify : 155 - [224 ÷ (8 × 4) - (-4) - {3 - 17 - 10}] pipeline-1023241
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railways | — | intermediate | |
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Simplify the following expression: 39 + [4 - {( -12) + 6 + (18 × 5 + 1 - 13 × 4)}] pipeline-1023257
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railways | — | intermediate | |
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23 − [24 − {25 − (26 − 27 − 28)}] =? pipeline-1022123
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railways | — | intermediate | |
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The value of 27 ÷ 3 − 27 × 0 + 1 = pipeline-1022121
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railways | — | intermediate | |
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5/2[5 ÷ 25 + 1/5{15 + 7/3(9 - 6/7) - 15}] = ? pipeline-848881
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railways | — | intermediate | |
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Find the difference between (i) and (ii). (i) 120 ÷ 24 × {(16 - 4) × (15 - 11)} ÷ 4 × 2 (ii) {(16 - 8) + (21 - 19)2} ÷ 12 × 204 × (1/2) ÷ 2 pipeline-988112
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railways | — | intermediate | |
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Simplify: 18 - [6 - {4 - (8.6 + 6.6 - 3.2)}] + 2 × 4 pipeline-854230
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railways | — | intermediate | |
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Simplify: [(34/12 + 11/16 - 12.5 ÷ 480/120 )(13/6 - 17/18)] × 12/11 pipeline-841805
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railways | — | intermediate | |
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What is the value of the following expression? 384 ÷ 25 × 3 + 8 = ? pipeline-846753
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railways | — | intermediate | |
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Solve the following expression: 20 - {7 - 24 ÷ (8 + 6 × 2 - 16)} pipeline-824966
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railways | — | intermediate | |
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What is the value of the following expression? 384 ÷ 25 × 3 + 8 = ? pipeline-802347
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railways | — | intermediate | |
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Solve: 5 of 5 of 5 ÷ 5 + 5 – 6 ÷ 3 × 4 + 2 + (3 ÷ 6 × 2) pipeline-854023
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railways | — | intermediate | |
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Find the value of 3 ÷ 3 of 3 × 6 ÷ (6 of 3) pipeline-854031
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railways | — | intermediate | |
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The value of 2 × 3 ÷ 2 of 3 × 2 ÷ (4 + 4 × 4 ÷ 4 of 4 – 4 ÷ 4 × 4) is: pipeline-802447
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railways | — | intermediate |