Cluster · Simplification using BODMAS Rule

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Clusters / #1219
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Simplification and BODMAS Order of Operations
Questions
436
Questions in this cluster
436 total
Question Category Subtype Difficulty

Simplify: \(\frac{2}{3} \ of \ 0.4 + (2 \times \frac{7}{5} + \frac{2}{3}) \div 6 \frac{1}{2} \)

pipeline-589178
rpf intermediate

Simplify:

3/8 of 6/7 - 9/7 × 1/3 ÷ 8/3

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rpf intermediate

Simplify -

54 + [6 - {( -11) + 15 + (22 × 5 + 1 - 18 × 3)}]

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Simplify: 18 - [6 - {4 - (8.6 + 6.6 - 3.2)}] + 2 × 4

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The value of (17 + 7 ÷ 4 × 4) ÷ (10 ÷ 2 of 5) of (7 × 7 ÷ 7 of 7 + 7 ÷ 7 × 7) is:

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Simplify: (11.2 × 0.36 + 0.42 × 6.4) ÷ (1.6 × 2.1) = ?

pipeline-539542
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Simplify the following.

24/5 ÷ {15/8 - 5/8(2/4 + 15/8 - 3/5)}

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Simplify -

42 × [78 ÷ {8 + 2 (16 - 7)}]

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Simplify: [(12/5 + 13/40) × (500 - 20 × 5)] ÷ [(13/3 + 1/9 ÷ 12/27) ÷ (15 - 7/4)]  ÷ [(218 × 159)/121]

pipeline-492581
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Simplify : 155 - [224 ÷ (8 × 4) - (-4) - {3 – 17 - 10}]

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14 ÷ (5 of 2 - 3) × 4(7 - 3) = ?

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What will come in place of question mark (?) in the following question?

28/3 ÷ {17/4 - 1/3 × (7/2 - 5/4 - 5/12)} = ?

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What will come in the place of question mark (?) in the following:

\(3{\frac{1}{3}} + 2{\frac{1}{2}} - \frac{3}{8}\ of\ 6\frac{2}{3} =\ ?\)

pipeline-484304
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 Simplify: \(\frac{2}{3} \ of \ 0.4 + (2 \times \frac{7}{5} + \frac{2}{3}) \div 6 \frac{1}{2} \)

pipeline-489682
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The value of 3 × 2 ÷ 3 of 12 – 3 ÷ 2 × (2 – 3) × 2 + 3 ÷ 2 is:

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What is the value of the following expression?

384 ÷ 25 × 3 + 8 = ?

pipeline-489664
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\(8\frac15 + 7\frac56-9\frac15-3\frac13=?\)

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(4/7) × (9/14) ÷ (16/21) × ? = 1

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(4 + 4 × 18 – 6 – 8) / (123 × 6 – 146 × 5) = ?

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Simplify the following expression.

[7 ÷ 2 × (8.35 + 1.3 + 2.42)]

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(5.25 × 6 × 4) ÷ 7 – 2 = ?2

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(4/5) × ? × (3/7) = (16/105)

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89 - [16 - {( -18) + 24 + (17 × 8 + 4 - 15 × 6)}] = ?

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2 – [ 2 – { 2 – 2 ( 2 + 2 ) } ] = ?

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(15/8) - (4/9) + (8/7) + (11/5) - (12/7) = ?

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5004 ÷ 139 – 6 = ?  

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Find the value of 1/p.

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\(7\dfrac{1}{3}+2\dfrac{1}{2}-1\dfrac{1}{6}+3\dfrac{5}{6}=?+7\dfrac{1}{7}\times14\)

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(2/3) + (4/3) × (3/2) + (5/2) × (2/6) = ?

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(5/4)/(9/16) – 1/8 + 1/12 = ? + (1/6 × 3/2)

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(1/2) ÷ (3/2) ÷ (5/2) ÷ (5/8) ÷ (6/7) = ?

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[(19/3 - 13/6 + 1/2) - 17/4 + (21/8 ÷ 7/2)] = ?

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banking intermediate

(14/27 × 9/28) ÷ 3/56 × 2/9 = ?

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banking intermediate

[–14 × 5 + (–49)] – [(96 + 32) ÷ 16] ÷ (–8) = ?

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The value of 8 ÷ [(9 - 5) ÷ {(4 ÷ 2 of 4) - ( 8 ÷ 8 of 16) + (4 × 2 ÷ 8)}] is?

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\(23\dfrac{8}{9}\) + \(15\dfrac{7}{9}\) - ? = \(12\dfrac{1}{3}\) × \(\dfrac{2}{3}\)

pipeline-1066187
banking intermediate

[3/2 + 1/2{3/4 - 1/2(7/8 - 3/4)}] = ?

pipeline-1066039
banking intermediate

\(\left[ 9 \frac{2}{7} + 2 \frac{2}{9} - \left( \frac{19}{14} \div \frac{9}{12} \right) \right] - 3 \frac{44}{63} = ? \)

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(1/4) × (32) – (18/3) – (2) = ?

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32 ÷ [{42 of (63 ÷ 7 + 3)% of 25} ÷ 2(5 – 3 + 4 + 1)] = ?

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2 (1/7) + 4 (3/5) – 3 (1/7) + 5 (1/10) = ?

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\(3\frac{4}{7} \div 2\frac{1}{2}-5\frac{3}{7}+3\frac{3}{8}of4\frac{4}{3}\) = ?

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(1/3 + 5/7 - 3/4) × 28/125 = ?

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(47/8) - (37/9) + 24/7 + 36/5 - 28/7 = ?

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(4/6) ÷ (8/3) + 2 × (4/7) – 3[4 × (1/12)] = ?

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(7/8) + (7/9) - (7/10) = ?

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(17/27 × 9/34) ÷ 5/42 × 15/14 = ?

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(0.2 × 0.2 × 0.01) ÷ (0.1 × 0.1 × 0.02) = ?

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If \(\frac{15}{8} + [\{\frac{4}{5} \) of \( \frac{5}{12} \div \left(1\frac{1}{15})\right\} \times 1\frac{7}{12}]\) is expressed in the form of \(\frac{a}{b}\) where a and b are integers and relatively prime to each other, the value 4b - a is:

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The value of (\(1\over2\)of 1\(1\over2\)) ÷ (3\(1\over2\)- 1\(1\over4\)) of 1\(1\over2\) - 1\(1\over2\) ÷ 2\(1\over4\)+ 1\(1\over3\) is:

pipeline-1296630
defence intermediate
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