Cluster · Simplification using BODMAS Rule
| Question | Category | Subtype | Difficulty | |
|---|---|---|---|---|
|
Which of the following is the least of all? pipeline-16288
|
quant | — | intermediate | |
|
If A = 2/3 ÷ 4/9, B = 6/11 × 33/12 and C = 1/3 × 9/2, then what is the value of A × B - C? pipeline-363260
|
quant | — | intermediate | |
|
42 + [15 - {( -21) + 27 + (18 × 6 + 1 - 17 × 4)}] = ? pipeline-429520
|
english | — | intermediate | |
|
{7 - (7 × 7) ÷ (7(7 - 4))} ÷ {7 ÷ 7 + 7 - 7(7 ÷ 4)} = ? pipeline-276346
|
english | — | intermediate | |
|
\(3\frac{4}{7} \div 2\frac{1}{2}-5\frac{3}{7}+3\frac{3}{8}of4\frac{4}{3}\) = ? pipeline-104825
|
english | — | intermediate | |
|
\({13\frac{5}{3}}\times{7\frac{5}{11}}\div {5\frac{6}{7}} + 13\frac{3}{8}\) = ? pipeline-12105
|
english | — | intermediate | |
|
\(23\dfrac{8}{9}\) + \(15\dfrac{7}{9}\) - ? = \(12\dfrac{1}{3}\) × \(\dfrac{2}{3}\) pipeline-216098
|
english | — | intermediate | |
|
\(({12\frac{4}{3}}\times{6\frac{3}{8}} \div 2\frac{3}{7}) - 21\frac{3}{2}\) = ? pipeline-46770
|
english | — | intermediate | |
|
(1/8) × (3/8) + (4/8) ÷ (5/8) + (7/8) - (9/8) = ? pipeline-56777
|
english | — | intermediate | |
|
The value of 9 × 6 ÷ 24 + 8 ÷ 2 of 5 - 30 ÷ 4 of 4 + 27 × 5 ÷ 9 is ? pipeline-19310
|
reasoning | — | intermediate | |
|
Simplify: 18 - [6 - {4 - (8.6 + 6.6 - 3.2)}] + 2 × 4 pipeline-49137
|
reasoning | — | intermediate | |
|
The value of 2 × 3 ÷ 2 of 3 × 2 ÷ (4 + 4 × 4 ÷ 4 of 4 – 4 ÷ 4 × 4) is: pipeline-2028
|
reasoning | — | intermediate | |
|
Simplify - 54 + [6 - {( -11) + 15 + (22 × 5 + 1 - 18 × 3)}] pipeline-225295
|
reasoning | — | intermediate | |
|
The simplified value of pipeline-7016
|
reasoning | — | intermediate | |
|
The simplified value of 3 × 2 ÷ 3 of 2 × 3 ÷ (5 + 5 × 5 ÷ 5 of 5 – 5 ÷ 10 of 1/5) is: pipeline-6867
|
reasoning | — | intermediate | |
|
The value of: [25 + 8 ÷ 2 - {16 + (14 of 7 ÷ 14) - (18 ÷ 12 of \(\frac{1}{2}\))}] = ? pipeline-303955
|
reasoning | — | intermediate | |
|
Simplify the following expression. \(\frac{3\frac{1}{2}+5\frac{1}{3}\div1\frac{1}{3}\times5\frac{1}{4}-5\frac{1}{2}}{1\frac{1}{2}\times 1\frac{2}{3}-6\frac{1}{2}}\div7\times 2\) pipeline-301479
|
reasoning | — | intermediate | |
|
The value of (5 + 3 ÷ 5 × 5) ÷ (3 ÷ 3 of 6) of (4 × 4 ÷ 4 of 4 + 4 ÷ 4 × 4) is: pipeline-6663
|
reasoning | — | intermediate | |
|
The simplified value of pipeline-7800
|
reasoning | — | intermediate | |
|
The value of \(\frac{2}{7} - \frac{3}{8} - \left[2 \frac{1}{4} \div 3 \frac{1}{2} \text{ of } 1 \frac{1}{3} + \left( 1 \frac{17}{40} - \left( 3 - 1 \frac{1}{5} - \frac{3}{8} \right) \right){} \right] \) is: pipeline-304134
|
reasoning | — | intermediate | |
|
Simpify:
pipeline-14831
|
reasoning | — | intermediate | |
|
What is the simplified value of the following?
pipeline-303015
|
reasoning | — | intermediate | |
|
The value of 25 ÷ 10 - (\(\frac{7}{4}\)×\(\frac{1}{3}\)) of \(\frac{6}{5}\)+\(\frac{14}{3}\)×\(\frac{9}{10}\)+(\(\frac{1}{5}\)÷\(\frac{1}{25}\)) is: pipeline-304113
|
reasoning | — | intermediate | |
|
The value of
pipeline-303189
|
reasoning | — | intermediate | |
|
The value of 5 ÷ 5 of 5 × 2 + 2 ÷ 2 of 2 × 5 – (5 – 2) ÷ 6 × 2 is: pipeline-6344
|
reasoning | — | intermediate | |
|
Find the value of the following expression:
pipeline-304316
|
reasoning | — | intermediate | |
|
Find the value of pipeline-6015
|
reasoning | — | intermediate | |
|
The value of 3 × 2 ÷ 3 of 12 – 3 ÷ 2 × (2 – 3) × 2 + 3 ÷ 2 of 3 is: pipeline-5720
|
reasoning | — | intermediate | |
|
The value of 3 × 2 ÷ 3 of 12 – 3 ÷ 2 × (2 – 3) × 2 + 3 ÷ 2 is: pipeline-7907
|
reasoning | — | intermediate | |
|
What is the value of \( \frac{36 \div 9 \times 5 \div 15 + 7 \times 3}{6 \div 12 \times 3 \div 12 + 8 \times 3} \) pipeline-1306244
|
mp_police | — | intermediate | |
|
Find the value of y in the expression: \(2\frac{3}{7} \times [(11\frac{2}{6}\div({25\over18} + 2\frac{5}{6} - {7\over36}))] = y \div 72.5\times204\) pipeline-1306136
|
mp_police | — | intermediate | |
|
Find the value of 40 – [20 – {14 – (16 – 6 × 4 – 2)}]. pipeline-1306152
|
mp_police | — | intermediate | |
|
The value of \(1 \div 2 + 3 - 5 \times {1\over3} of 15 - {(75\div(28-3))}\). pipeline-1305730
|
mp_police | — | intermediate | |
|
The value of 66 ÷ [34 - (32 of 2 - 4) ÷ (4 × 15)] is equal to: pipeline-1300190
|
mp_police | — | intermediate | |
|
Simplify. 325 + 276 ÷ [150 - {9 × 9 +(83 - 4 × 15)}] pipeline-1305836
|
mp_police | — | intermediate | |
|
The value of 36 ÷ (8 × 3) − [3 ÷ {4 × { 3 × 4 ÷ (5−9) + 6 }}] lies between pipeline-1302129
|
mp_police | — | intermediate | |
|
Simplify the following expression: \(\frac{2}{3} + \frac{4}{9} \div \left( \frac{7}{2} - \frac{5}{6} \right)\) pipeline-1302115
|
mp_police | — | intermediate | |
|
Find the value of the given expression. \( \frac{\left( 4\frac{1}{3} + 3 \frac{1}{3} \times 1 \frac{4}{5} \div 3 \frac{3}{4} \times \left( 1 \frac{1}{2} + 1 \frac{1}{3} \right) \right)}{\left( \frac{2}{3} \div \frac{5}{6} \times \frac{2}{3} \right) } \) pipeline-1290627
|
mp_police | — | intermediate | |
|
Simplify: 20 × [24 ÷ 105 × {75 × 119 ÷ (15 × 17) }] pipeline-1290632
|
mp_police | — | intermediate | |
|
The value of 2405 ÷ 13 × 6 + 35 is: pipeline-1292979
|
mp_police | — | intermediate | |
|
Simplify: 0.077÷7-0.005÷5 pipeline-1291611
|
mp_police | — | intermediate | |
|
Simplify. 963 + 306 × 102 ÷ 6 - 86 + (218 - 15) pipeline-1288139
|
mp_police | — | intermediate | |
|
Simplify the following. \((5-{15\over16})\times 1{12\over13}\) pipeline-1273608
|
mp_police | — | intermediate | |
|
What is the value of \(\frac{\frac{1}{1}\div \frac{1}{2}\times \frac{1}{2}+\frac{1}{2}\times \frac{1}{2}\div \frac{1}{2}}{\frac{1}{4}\times \frac{1}{4}\div \frac{1}{2}+\frac{1}{4}\div \frac{1}{4}\times \frac{1}{2}-\frac{1}{4}\div \frac{1}{2}\times \frac{1}{2}}\)? pipeline-1288129
|
mp_police | — | intermediate | |
|
Evaluate the following expression. \([{-4\over7} \div{1\over12}]\div[{-4\over5}\times \{(-2)-({-2\over7})]\) pipeline-1286126
|
mp_police | — | intermediate | |
|
Simplify 6 × [ 28 ÷ 84 × {36 × 49 ÷ ( 6 × 7 )}] pipeline-1273623
|
mp_police | — | intermediate | |
|
Simplify the following expression. pipeline-1286146
|
mp_police | — | intermediate | |
|
Simplify. 325 + 276 ÷ [150 - {9 × 9 +(83 - 4 × 15)}] pipeline-1318270
|
bihar_police | — | intermediate | |
|
What is the value of [8.13] + [0.62] + [2.2]? [x] is the greatest integer function. pipeline-435864
|
bihar_police | — | intermediate | |
|
The value of 9 - 5 × 6 + {29 - (7 - 2)} ÷ 8 is : pipeline-1363815
|
rajasthan | — | intermediate |

is:

is:
